Question

[9.05] Solve 3x2 + 4x + 2 = 0. Round solutions to the nearest hundredth.

Answer 1

use quadratic formula

Answer 2

need more help?

Answer 3

Yeah

Answer 4

quadratic formula:
\[\LARGE x = \frac{-b \pm \sqrt{b^2 = 4ac}}{2a}\]

Answer 5

that = is a -

Answer 6

\[\begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} & {{\rm{when}}} & {ax^2 + bx + c = 0} \\ \end{array} \]
you are given\[ 3x^2 + 4x + 2 = 0\]
can you tell me what a b and c are?

Answer 7

so substitute
a = 3
b = 4
c = 2