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two truck drivers leave a cafe at the same time traveling in opposite directions. one truck goes 7 mph faster than the other one. after 4 hours they are 404 miles apart. how fast is each truck going?
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let x = speed of truck A x + 7 = truck B <--because 7 mph faster after 4 hours the distance of truck B would be 4(x+7) according to distance = speed x time after 4 hours the distance of truck A would be 4x according to distance = speed x time it says that the distance between them is 404 so let's add 4x + 4(x+7) = 404 4x + 4x + 28 = 404 8x = 404 - 28 8x = 376 solve for x
do you get that?
yes i get it. thanks
<tips hat>
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