Question

a train travels some distance with a speed of 30 km/h. and then it returns to 45 km/h. calculate the average speed

Answer 1

@ash2326 @AccessDenied @annas @Rohangrr

Answer 2

the average speed is (s1*t1 + s2*t2)/(t1 + t2), where s1 and s2 are the speeds and t1 and t2 are the respective times.

Answer 3

solve it further

Answer 4

@lgbasallote @lalaly

Answer 5

Let's say the distance is x. Total distance will be 2x.

Time for first trip = x/30
Time for second trip = x/45

Average speed = 2x/(x/30 + x/45) = 2x/(x/18) = 36 km/h

Answer 6

okay thats final solution then

Answer 7

Why do you even need to ask if that is the final solution. Do it yourself and if you get that then it's right

Answer 8

be quiet @Romero

Answer 9

and I actually don't think that's the right answer btw

Answer 10

Distance=D
Total Distance =2D
Time one way=D/V1=D/30
Time the other way: D/V2=D/45
Total Time =T1+T2=D/30+D/45

Average Speed=Total Distance/Total Time = 2D/(D/30+D/45)=2/(1/30+1/45)=36Km/h

Answer 11

thank u all guys