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What is the difference in the sum of the squares & the difference of squares of 'n' & 'a' when \[\LARGE{\sqrt{a^{n-2}}.3^{a+2} \over 6^n.\left( n \over 2 \right)-\left( 1-{n \over2} \right)}=\LARGE{\frac{1}{4\sqrt{2^n}}} \] & sum of 'a' & 'n' is 12:-
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NTSE rocks @mathslover
:D i will answer u soon i am doing my homework sorry
http://cbse.meritnation.com/study-online/solution/Hindi/pSZhSYDFEStqII8bXRCfuw!! proof :)
k np:)
@mathslover Plz help:)
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