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Physics 18 Online
OpenStudy (anonymous):

please take a look at this.

OpenStudy (anonymous):

OpenStudy (anonymous):

use Kirchhoff circuit law and distribute the current, i was not able to find ant symmerty to makt the question easy

OpenStudy (anonymous):

do i need to solve?

OpenStudy (anonymous):

Here goes the solution. I have applied Kirchoff by loops. It could also be solved by nodes Any doubt, let me know

OpenStudy (anonymous):

@CarlosGP how r u able to make so neat attachemets and post it

OpenStudy (anonymous):

Power Point using Equations Editor and save as pdf

OpenStudy (anonymous):

where is equation editor?

OpenStudy (anonymous):

Insert Object command

OpenStudy (anonymous):

why did you use 1/2 on the formula to get power? @CarlosGP

OpenStudy (anonymous):

Because I have assumed 240V is peak voltage. Should it be R.M.S. then there is no need to divide by 2 for RMS=PEAK/SQROOT(2)

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