Question

Find the domain and range of f(x0 = (x^2-9)/(x-3)

Answer 1

Domain = R-{3}

Answer 2

\[f(x)=\frac{(x-3)(x+3)}{(x-3)}\]

and x can not be 3 why?

Answer 3

then range

Answer 4

ok range
f(x)=x+3
am i right?

Answer 5

so range is all real numbers??

Answer 6

no because u cant let x=3

Answer 7

Range = R-{6}

Answer 8

hw

Answer 9

f(3)=3+3=6

Answer 10

i got it thxxx

Answer 11

plzz take my new question