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If you were to use the substitution method to solve the following system, choose the new system of equations that would result if z was isolated in the first equation. 2x – 5y + z = 15 4x – y + 3z = 15 3x – 2y + 2z = 13 choices: 22x + 16z = 90 11x + 8z = 43 –18x – 14z = –60 –5x + 8z = 43 10x – 16y = –30 7x – 12y = –15 –2x + 14y = –30 –x + 8y = –17
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