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OpenStudy (anonymous):
What is the function inverse of f(x)= 2/3x-5 ?
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OpenStudy (anonymous):
y = 2/3x-5 ; find x in terms of y
OpenStudy (anonymous):
x= 2/3y-5?
what confuses me is how to rearrange this eqn
OpenStudy (anonymous):
lol no
OpenStudy (anonymous):
we need to isolate x. can u take 5 to the other side.
OpenStudy (anonymous):
y(-5)= 2/3x?
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OpenStudy (anonymous):
nah, sign will change. y + 5 = 2/3x
OpenStudy (anonymous):
is it it addition? isnt the opposite of division multiplication?
OpenStudy (anonymous):
ya but 5 is subtracted from 2/3x, so it ll be added on the other side rite??
OpenStudy (anonymous):
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OpenStudy (anonymous):
ohh sorry. y = 2 / (3x-5)
means , 3x - 5 = 2 / y
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OpenStudy (anonymous):
(3x-5)/2 = y?
OpenStudy (anonymous):
nah u need to isolate x. 3x = (2 / y) + 5
x = (2 / 3y) + (5/3)
OpenStudy (anonymous):
omg im so confused.
OpenStudy (anonymous):
i thought the 5 was negative
OpenStudy (anonymous):
lemme sum it up for you
y = 2 / (3x-5)
3x - 5 = 2 / y
3x = (2 / y) + 5
x = (2 / 3y) + (5/3)
Inverse is (2 / 3x) + (5/3)
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OpenStudy (anonymous):
okay thanks !
OpenStudy (anonymous):
You're welcome :)
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