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2e^(-t)-2te^(-t)=0 ; solve for t
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I took out e^(-t)
Good start. What did the equation look like after you factored out e^(-t) ?
e^(-t) times (2-2t)=0....then I divided both sides by (2-2t)
so I get e^(-t) equals zero? how to you solve that
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you cannot
\(b^x\neq 0\) for any \(x\) so don't fret about it, that part you can ignore
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