4+log subscript 9(3x-7)=6
subtract 4 from both sides \[\log _{9} (3x - 7) = 2\] raise each side as a power of 9 and remember \[9^{\log _{9}(3x - 7)} = 3x - 7\] then \[(3x - 7) = 9^2\] 3x - 7 = 81 3x = 88 I'll let you finish the problem
did u get 261?
where did you get 261 from?
i subed the 88 in for x and did that whole problem over is that wrong??
the problem is asking you to find an x, so that when you put it into the original equation, it will be true. campbell figured out the 3x= 88 that means 3 times x (the number we are looking for) is 88 or x+x+x= 88 x is definitely less than 88 (it takes 3 of them to get 88) you solve for x by dividing both sides by 3
wow i feel slow -_-
If this were easy it would not be math
so with 3x=88 what is x?
Do you know how to find x if 3x=88 ?
no :/
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