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Mathematics 37 Online
OpenStudy (anonymous):

Multiply. (2x2 + 3x – 6)(x – 1)

jimthompson5910 (jim_thompson5910):

(2x^2 + 3x – 6)(x – 1) (x – 1)(2x^2 + 3x – 6) x(2x^2 + 3x – 6) - 1(2x^2 + 3x – 6) I'll let you finish up

OpenStudy (anonymous):

2x3 + 3x2 – 6x + 6 2x3 – 18x2 – 3x + 6 2x3 – 12x2 + 3x + 6 2x3 + x2 – 9x + 6

jimthompson5910 (jim_thompson5910):

What do you get when you distribute x(2x^2 + 3x – 6) ?

OpenStudy (anonymous):

would it be the first one?

jimthompson5910 (jim_thompson5910):

x times 2x^2 is ???

OpenStudy (anonymous):

2x^3

jimthompson5910 (jim_thompson5910):

x times 3x is ???

OpenStudy (anonymous):

3x^2 ?

jimthompson5910 (jim_thompson5910):

and x times -6 is ???

OpenStudy (anonymous):

-6x

jimthompson5910 (jim_thompson5910):

So x(2x^2 + 3x – 6) becomes 2x^3+3x^2-6x

jimthompson5910 (jim_thompson5910):

We must do the same for -1(2x^2 + 3x – 6)

OpenStudy (anonymous):

so the answer would be 2x^3+ 3x^2-6x+6 ??

jimthompson5910 (jim_thompson5910):

What is -1 times 2x^2 ???

OpenStudy (precal):

|dw:1341786818980:dw| you can use box multiplication as an alternative way to do this problem

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