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Multiply. (2x2 + 3x – 6)(x – 1)
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(2x^2 + 3x – 6)(x – 1) (x – 1)(2x^2 + 3x – 6) x(2x^2 + 3x – 6) - 1(2x^2 + 3x – 6) I'll let you finish up
2x3 + 3x2 – 6x + 6 2x3 – 18x2 – 3x + 6 2x3 – 12x2 + 3x + 6 2x3 + x2 – 9x + 6
What do you get when you distribute x(2x^2 + 3x – 6) ?
would it be the first one?
x times 2x^2 is ???
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2x^3
x times 3x is ???
3x^2 ?
and x times -6 is ???
-6x
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So x(2x^2 + 3x – 6) becomes 2x^3+3x^2-6x
We must do the same for -1(2x^2 + 3x – 6)
so the answer would be 2x^3+ 3x^2-6x+6 ??
What is -1 times 2x^2 ???
|dw:1341786818980:dw| you can use box multiplication as an alternative way to do this problem
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