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log subscript 6 x + log6 (x-5)=2
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Use The property : LogX+LogY=Log(x*Y) Can U do it now ?
not sure but ill try
Anyway ,Here is The Answer :: \[\Large Log_{6}x+Log_{6}(x-5)=2\] Using the Property that i posted : \[\Large Log_{6}(x*(x-5))=2\] Change it to Exponential: \[\Large 6^2=x^2-5x\] now factorize and solve it and get the value of x.
lost
where ?
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i multiplied the logs and got 0.6 put it in for x and the answers werent coming up
Did U follow My Steps ?
:/ yes
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