Question

Evaluate 3x^2-2xy+4y^2 for x=-3 y=2

Answer 1

Put x=-3 and y=2 into 3x^2-2xy+4y^2

3(-3)^2-2(-3)(2)+4(2)^2 = ...?

Answer 2

i have27+6-4+16=-21

Answer 3

81+12+64= 157

Answer 4

that answer is not right

Answer 5

3(-3)^2-2(-3)(2)+4(2)^2
= 3(9) - (-6)(2) + 4(4)
= 27 + 12 + 16
= ...?

Answer 6

55

Answer 7

i got 31??

Answer 8

@katiebugg Can you show your workings??

Answer 9

yeah hold on

Answer 10

the answer is 31

Answer 11

27-12+16=31

Answer 12

told you lol

Answer 13

No. You made a mistake or the question is wrong

Answer 14

For the middle term
-2(-3)(2)
= -2 ( -6)
= 12
negative times negative gives positive.

Answer 15

3(9)-2(-3)(2)+4(4)
27+12+16=55
i did i allways mess up the signs when i do it in my head :( sorry i need to stop that

Answer 16

@kaleeb20 55 is right

Answer 17

ok thank you guys

Answer 18

yeah idk y ur thankin us lol u did it!!

Answer 19

lol just trying to be nice dats all lol

Answer 20

i know lol thanks!!