Question

Approximate the real number solutions to the polynomial function f(x) = x3 - 4x2 - 4x + 16 .

Answer 1

x^3 - 4x^2 - 4x + 16
x^2 (x-4) - 4 (x-4)
(x^2-4) (x-4)
(x+4)(x-4)(x-4)

Answer 2

x = -4, x = -2, x = 2
x = -2, x = 2, x = 4
x = -4, x = -2, x = 4
x = -4, x = 2, x = 4

Answer 3

oh fk i messed up
x^3 - 4x^2 - 4x + 16 = 0
x^2 (x-4) - 4 (x-4) = 0
(x^2-4) (x-4) = 0
(x-2)(x+2)(x-4) = 0

Answer 4

hahaha so 2,-2, 4? makes more sence haha ty