Question

The equation of a curve is y=8x-x^2
Find the set of values of x for which y is greater/equal to -20.

Answer 1

\[x^2 - 8x +y = 0\]

As \(y \ge -20\)

Take y = -20 first:

\[x^2 - 8x - 20 = 0\]

\[(x-10)(x+2) = 0\]

\[x = 10 \quad x= -2\]

Answer 2

@waterineyes mmm how do you make it in the form of inequality ? ?