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OpenStudy (anonymous):
Find the range of 1/(x+2)
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OpenStudy (anonymous):
this one is an easy one!
OpenStudy (anonymous):
y= 1/(x+2)
OpenStudy (anonymous):
x = 1-2y/y
OpenStudy (anonymous):
y not equal 0
OpenStudy (anonymous):
you have a fraction, and a fraction is only zero of the numerator is zero right? in your case the numerator is 1, and so it is never 0
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OpenStudy (anonymous):
so Range = R-{0}
OpenStudy (anonymous):
is that correct
OpenStudy (anonymous):
yes you are right
OpenStudy (anonymous):
thxx
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