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What are the solutions of 3x2 + 4x = –5?
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3x^2 + 4x + 5 = 0 you can solve this by using quadratic formula for ax^2 + bx + c = 0 x = ( (-b +-sqrt(b^2 - 4ac)) / 2a
here a = 3 . b = 4 and c = 5 plug these into the above formula
I still dont get it, @Muskan can you help?
3x2+4x+5=0 -4+-\[\sqrt{4-4*3*5/2*3}\] -4+-\[\sqrt{-56/6}\]
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is it -66?
|dw:1341857021301:dw| |dw:1341857109169:dw|
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