Question

Find the value of the discriminant

3x2 - 5x + 6 = 0

Answer 1

it is in standard form already.

Answer 2

b^2-4 a c

Answer 3

well my question says find the discriminant and describe the number and type of roots

Answer 4

5^2-(4 * 3 * 6)

Answer 5

-47 so it has 2 imaginary roots

Answer 6

ohk thnks :)

Answer 7

are u sure its not 2 complex roots?

Answer 8

complex roots yes same thing i mean

Answer 9

wat about x2 + 5x + 6 = 0

Answer 10

it is standard form also

so

b^2-4 a c

5^2-(4*6)

Answer 11

which is 1 so it has 2 real roots :)

Answer 12

thnk u sooooo very much!!!!!!!!

Answer 13

i actually have 3 more if u dnt mind helping

Answer 14

thats if u dnt mind

Answer 15

remember the rulse is use


b^2-4 a c


if result=r r for result
r>0 it has 2 real roots
if r=0 then it has 1 root

if r<0 then it has 2 imiginary aka complex roots.

Answer 16

x2 + 5x + 6 = 0

Answer 17

brb

Answer 18

ohk :(

Answer 19

one more
here are your formulas
ax^2+bx+c=0
b^2-4 a c

youare given
x2 + 5x + 6 = 0
a b c

so plug that into

b^2-4 a c
5^2-4*1*6=1

so it has 2 real roots

Answer 20

so it has 2 rational roots but wat is the number because it is not 1

Answer 21

what do you mean?

Answer 22

im dumb at math so excuse me lol but wat does D=?

Answer 23

D=1 in the very last one

Answer 24

how?

Answer 25

im sorry lol i gave u the wrong problem!!! lol i meant to put x2 - 8x +16 = 0... soo sorry!

Answer 26

i was thinking that :P

Answer 27

i told u i was sloww lol

Answer 28

x2 - 8x +16 = 0
a b c
b^2-4 a c
8^2-4*16=0

so it has one real root

Answer 29

and D=0 rite?

Answer 30

rite!

Answer 31

thnks hun!