Solve 2 log2 2 + 2 log2 6 – log2 3x = 3

Question

anonymous · Answer

the log(4)(36)-log36=3

anonymous · Answer

hmm ,from where you got (36) ???

anonymous · Answer

i meant to put log(4)(36)-log3x=3 sorry

anonymous · Answer

right now i really just don't know where to go from    log144-log3x=3

anonymous · Answer

Wow I would have never gotten that thank you! but thats not one of the answer choices

anonymous · Answer

ok im confused

anonymous · Answer

thay are x= 2,x=6,x=16,x=18

anonymous · Answer

Lets begin step by step First we will get the power inside the log :
$$\Large Log_{2}2^2+Log_{2}6^2-Log_{2}(3x)=3$$
Then according the the property that i showed to you in the last Post We will combine them:
$$\Large Log_{2}\frac{2^2*6^2}{(3x)}=3$$
Lets change it to exponential :
$$\Large \frac{2^3}{1}=\frac{2^2*6^2}{(3x)}$$
Now lets change it to an equation:
$$\Large \color{red}{24x=144}$$
Divide by 24
$$\Huge \color{blue}{x=6}$$

anonymous · Answer

Got it ?

anonymous · Answer

ooh ok i got it thanks