Question

find the indefinite integral

Answer 1

\[\int\limits \cos^3(2x) \sin^2(2x)dx\]

Answer 2

u = sin(2 x)
du = 2 cos(2x)dx
\[
\int (1-u^2)u^2 \frac {du}2
\]

Answer 3

\[1/2 \int\limits u^2-u^4du?\]

Answer 4

yes

Answer 5

\[\frac{1}{2} [\frac{u^3}{3} -\frac{u^5}{5}] +c\]

Answer 6

yes
\[
\int \frac{1}{2}
\left(1-u^2\right) u^2 \,
du=\frac{u^3}{6}-\frac{u^5}
{10}
\]

Answer 7

\[\frac{u^3}{6} -\frac{u^5}{10} +c?\]

Answer 8

:)

Answer 9

+C

Answer 10

\[\frac{\sin(2x)^3}{6} -\frac{\sin(2x)^5}{10} +c?\]