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OpenStudy (anonymous):
State the zero of the following function: y= 2x(x-1)(x+2)(x-2)
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OpenStudy (shane_b):
Since it's already factored it will be x = 1, x = 2, x = -2, x = 0
OpenStudy (anonymous):
thanks !
OpenStudy (shane_b):
N worries, good luck!
OpenStudy (anonymous):
how about when theres only a constant
OpenStudy (anonymous):
5(2x+3)(4x-5)(x+7)
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