Approximate the real number solution(s) to the polynomial function f(x) = x^3 + 2x^2 – 5x – 6 ? Help Please? Tried ..didnt get right.

Question

anonymous · Answer

did you try cheating?

anonymous · Answer

Put x = -1
Will you get 0??

anonymous · Answer

are there 3 real sols

anonymous · Answer

-1 is one of them..

anonymous · Answer

No? I tried plugging the solutions in the equation but I dont think thats how you do It so i wanted someone to explain to me. Dont have to be a jerk.

anonymous · Answer

see I tried -1 , I guess I did it wrong becasue it didnt come out to equaling 0.

anonymous · Answer

this one factors, but it may be hard to see that it was cooked up
try 1 first, if that doesn't work, try $-1$ the only integer possibilities are $\pm1,\pm2,\pm3,\pm6$

anonymous · Answer

The three solutions will be:
-1, -3 and 2..

anonymous · Answer

yes 3 solutions since the leading coefficient has a exponent of 3

anonymous · Answer

x^3 + 2x^2 – 5x – 6=0
 x^2(x-2) +4x(x-2) +3=0 
(x-2)(x^2 +4x+3)=0 
(x-2)(x+1)(x+3)=0
x=-3,-1,2

valpey · Answer

I must have missed the part where we are asked to solve for f(x) = 0.

anonymous · Answer

Yes..

All the 3 solutions are real..