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1 - 3 (2x − 8) = 4
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@mathavraj
2/3x-8/3=4 2/3x=20/3 x=10/9
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\[\frac 13 (2x - 8) = 4\] cross multiply \[2x - 8 = 4 \times 3\] \[2x - 8 = 12\] \[2x = 12 + 8\] \[2x = 20\] \[x = \frac{20}{2}\]
\[\frac{1}{3}(2x-8)=4\] multiply both sides by 3 to get rid of annoying fraction and start with \[2x-8=12\]
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or if you want that other method \[\frac 13 (2x - 8) = 4\] \[\frac{2}{3} x - \frac{8}{3} = 4\] multiply everything by 3 \[2x - 8 = 4 \times 3\] it will now go on the same line METHOD 3: \[\frac 13 (2x - 8) = 4\] \[\frac 23 x - \frac 83 = 4\] \[\frac{2x - 8}{3} = 4\] \[2x - 8 = 4 \times 3\] yada yada...
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