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simplify the expression (4x^2/6y^4)^3
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\[\LARGE (\frac{4x^2}{6y^4})^3 \implies \frac{(4x^2)^2}{(6y^4)^3} \implies \frac{4^2 x^{2 \times 2}}{6^3 y^{4\times 3}}\] lol i hope you understand that
oops lol made a mistake
let me fix it
ok
\[\huge (\frac{4x^2}{6y^4})^3 \implies \frac{(4x^2)^3}{(6y^4)^3} \implies \frac{4^3 x^{2 \times 3}}{6^3 y^{4 \times 3}}\] i hope you understand that lol
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kind of thanks
<tips hat>
(4x^2/6y^4)3 = (64x^6/216x^12)=(8/216x^6)
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