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Simplify x^2 - 10x - 24/ x^2 -3x -108
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\[\frac{x^2 - 10x - 24}{x^2 - 3x - 108} \implies \frac{(x-12)(x+2)}{(x-12)(x+9)}\]
i just factored it out
x2−10x−24x2−3x−108⟹(x−12)(x+2)(x−12)(x+9)
I see what I did wrong with you posting that thank you.
factored it
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welcome
becasue I thought it was (x+12)(x-2)/(x-12)(x+9) so I was like wth I cant cancel out and none of the answers were that
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