Question

A countrys population in 1993 was 83 million. In 2001 it was 87 million. Estimate the population in 2004 using the exponential growth formula. Round your answer to the nearest million.
P=Ae^kt

Answer 1

find the rate k
at 1993, t = 0
at 2001, t = 8

so in 2001,
87 million = (83 million) e^(8k)
87/83 = e^(8k)
ln(87/83) = 8k
\[\huge \frac{\ln(\frac{87}{83})}{8} = k\]

find k then
at 2004, t = 11

Answer 2

I still don't understand

Answer 3

sorry for the english

P=Ae^(kt)

P = population after t years
A = population in 1993, 83 million
k = rate of growth
t = years after 1993

first we need to find k by substitute the data given for year 2001, shown in my first reply

after you got k, just substitute t = 11 (year 2004)

P = (83 million)e^(11k)