12<2^(m/n)<13 ..... what are the smallest possible integers for m and n?
its a challenging quesion...
positive integers?
n=3 and m=11 ?
@aceace
let m/n =q => 12 < 2^q < 13 clearly,q will be between 3 and 4 2^q = 12 shall give our ans taking log to base 10, q(0.3) = 2(0.3) + (0.5) q = 11/3 so i go with @mukushla
wolfram tells me 3.485 approx => 697/200
can you please explain the log part...
log(2) and log(3) to base 10 are basic ones.. log2 = 0.3010 and log 3 = 0.5 approx..
\[12<2^{m/n}<13 \\ take \ \ \log \\ \log 12<\frac{m}{n} \log 2<\log 13 \\ \frac{\log 13}{\log 2}<\frac{m}{n} <\frac{\log 13}{\log 2}\\ 3.5<\frac{m}{n}<3.7\]
simply u can see m=11 and n=3 is your answer
how do you see that those integers are the answer?
how do you see that those integers are the answer?
how do you see that those integers are the answer?
how do you see that those integers are the answer?
how do you see that those integers are the answer?
how do you see that those integers are the answer?
how do you see that those integers are the answer?
note that inequality sign didnt reverse since we were taking base >1
yep
i see.. thanks
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