Question

Note: Its a THEORY on DERIVATION 'velocity time'

Answer 1

\[\huge v=u+at \]
Let a body have an Initial Velocity\[ 'u' \] and uniform acceleration \['a' .\]
At any time \['t' \quad if \quad 'v'\] is the velocity.
\[Accelaration=\frac { Change\quad \in \quad Velocity }{ time\quad taken } \]
\[=\frac { v-u }{ t } \]
\[\therefore \quad v=u+at \]