In t1= 2sec, the accel. of a particle in circular movement in counterclockwise way is (6,00m/s2)I + (4m/s2)j. It's move with constant speed. In t2=5sec, it's accel. is equals to 4i-6j. What's the radius of the trajectory of the particle if the diff. T2-t1 is lower than one period.

Question

anonymous · Answer

do you know about the dot product of vectors?

jpsmarinho · Answer

Yes!

anonymous · Answer

Then, find the angle between the two acc vectors by using|dw:1341947007316:dw|