Question

The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width.

16
7
8
21
24

Answer 1

2l+2w=48 l=2w+3
iGot that far.

Answer 2

not sure what you mean, maybe it's this

2l + 2w = 48
2x3 + 2w = 48
6 + 2w = 48
2w = 42
w = 21

Answer 3

$$ l = 2w +3 $$

$$ 2(l + w) = 48 $$

$$ 2( (2w +3) + w) = $$

$$ 6w + 6 = 48 $$

$$ w = 7 , l = 17 $$

Answer 4

2L+2W=48
so L+W=24
and L=3+2W
so 3+2W+W=24
=>3W=21 so W=7
and therefore L=2x7+3=17

Answer 5

17 is not an option, only those above