Question

compute the limit
lim(8x-x^2-16)^1/2 as x goes to 4 my anserw was -32 is that right?

Answer 1

substitute x by 4 in the expression:
(8*4 -4^2-16)^1/2=(32-32)^1/2=0

Answer 2

so 0 would be the anserw?

Answer 3

yes

Answer 4

thank you