Question

\[6^{2}+9x-12\div3x\]

Answer 1

Divide each terms by \(3x\)

first of all :-
\(6^2 = 36 \)
36 + 9x - 12 = 24 + 9x
is this clear?

Answer 2

Now divide each terms by 3x

Answer 3

\[\frac{24}{3x}+ \frac{9x}{36}\]Now simplify this.

Answer 4

ok thank you

Answer 5

Welcome :)

Answer 6

Did you get the answer?

Answer 7

no i'm working on it

Answer 8

Oops! i made a small typo: it 3x not 36 in the denominator ,sorry!
\[\frac{24}{3x}+ \frac{9x}{3x}\]

Answer 9

l0l its ok