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If r= 25 & y= 15, then x= ?
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\[x^2 + y^2 = r^2\] \[x^2 = r^2 - y^2\] \[x = \sqrt{r^2 - y^2}\] \[x = \sqrt{25^2 - 15^2}\]
20?
you are correct
if x= 10 and y= 6 what is r? how would i set that up?>
\[\Large x^2 + y^2 = r^2\] \[\Large (10)^2 + (6)^2 = r^2\] \[\Large 100 + 36 = r^2\] I'll let you finish
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i got 4 square root 17 ?
\[\Large 100 + 36 = r^2\] \[\Large 136 = r^2\] \[\Large r^2 = 136\] \[\Large r = \sqrt{136}\] \[\Large r = \sqrt{4*34}\] \[\Large r = \sqrt{4}*\sqrt{34}\] \[\Large r = 2\sqrt{34}\]
So you were close
somehow you factored out an additional 2
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