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How many and of what type are the solutions to x2 + 10x + 25 = 0? No real solutions Two identical rational solutions Two different rational solutions Two irrational solutions
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solve for the discriminant \[b^2 - 4ac\] \[(10)^2 - 4(1)(25)\] \[100 - 4(25)\] \[100 - 100\] \[0\]
so how many solutions?
SO ITS NO REAL SOLUTIONS
b^2 - 4ac > 0 two real solutions b^2 - 4ac = 0 one real solution b^2 - 4ac < 0 no real solution
so what do you think?
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x² + 10x + 25 = 0 We have this : b² - 4ac = 10² - 4.25 = 0 => B.Two identical rational solutions
so its what ashley said! lol
Lol yup!
yes its B
yup
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thank you everyone.. you guys and girls should help me on my other one im about to post lol
Your welcome. & why nott (:
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