Question

Completing the square 16d^2= 25

Answer 1

I dont think thats right, because from that info I need to find the vertex

Answer 2

(4d)^2=25
4d=+/-sqrt(25)
d=5/4 and d=-(5/4)

I think this should be it?

Answer 3

It should be like this:

\[16d^2 - 25 = 0\]

\[(4d)^2 - 5^2 = 0\]

\[(4d + 5)(4d - 5) = 0\]

\[d = \frac{5}{4} \quad Or \quad d= \frac{-5}{4}\]

Answer 4

I accidentally bracketed the latter d. My bad.