Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it.

Question

ajprincess · Answer

jst a moment then.

ajprincess · Answer

$$sin(A+B)=sinAcosB+cosAsinB$$
$$cos(A+B)=cosAcosB-sinAsinB$$


$$sin(A-B)=sinAcosB-cosAsinB$$
$$cos(A-B)=cosAcosB+sinAsinB$$

valpey · Answer

You can also write:
$$sin(A\pm B)=sinAcosB\pm cosAsinB$$
$$cos(A\pm B)=cosAcosB\mp sinAsinB$$