Question

Note to the viewers: This is nt a question. I made a mistake in certain portion of my previous post which was a tutorial on trigonometric identities and this is the correct version of it.

Answer 1

jst a moment then.

Answer 2

\[sin(A+B)=sinAcosB+cosAsinB\]
\[cos(A+B)=cosAcosB-sinAsinB\]


\[sin(A-B)=sinAcosB-cosAsinB\]
\[cos(A-B)=cosAcosB+sinAsinB\]

Answer 3

You can also write:
\[sin(A\pm B)=sinAcosB\pm cosAsinB\]
\[cos(A\pm B)=cosAcosB\mp sinAsinB\]