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Mathematics 49 Online
OpenStudy (anonymous):

tan(19 pie/3) =?

OpenStudy (anonymous):

sorry there is mistake

OpenStudy (shubhamsrg):

19 = 16+3 how about now ?

OpenStudy (anonymous):

mmmm pie

OpenStudy (anonymous):

now look the question

OpenStudy (anonymous):

i got it the asnwwe is sqrt 3

OpenStudy (anonymous):

thxxx for responding to my message

OpenStudy (anonymous):

the period of tangent is \(\pi\) and since \(\frac{19}{3}=6\tfrac{1}{3}\) this is the same as finding \(\tan(\frac{\pi}{3})\) which is indeed \(\sqrt{3}\)

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