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tan(19 pie/3) =?
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sorry there is mistake
19 = 16+3 how about now ?
mmmm pie
now look the question
i got it the asnwwe is sqrt 3
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thxxx for responding to my message
the period of tangent is \(\pi\) and since \(\frac{19}{3}=6\tfrac{1}{3}\) this is the same as finding \(\tan(\frac{\pi}{3})\) which is indeed \(\sqrt{3}\)
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