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A train starting from rest attains of 72 km/h in 5mins assuming that acc. is uniform a. The acc. b. the distance traveled by the train for attaining this velocity.
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@Yahoo! CAN U
yup plzz wait
@satellite73
v= u + at
use this
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u =0 becoz starting from rest
72 km/h = 20m/s
5 min = 300s
now find acceleration
use the laws of motion (physics)
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Didn't we do this not too long ago?\[a=\frac{Delta V}{\Delta T}=\frac{20m/s}{(5*60s)}=?\]
20 = 0 + 300a a = 20/300 = 0.066
m/s^2
s = ut + 1/2 a t^2 s = 0 + 1/2 * 0.06 * 300 *300 = 2700 m
yup
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