Question

A train starting from rest attains of 72 km/h in 5mins
assuming that acc. is uniform
a. The acc.
b. the distance traveled by the train for attaining this velocity.

Answer 1

@Yahoo! CAN U

Answer 2

yup plzz wait

Answer 3

@satellite73

Answer 4

v= u + at

Answer 5

use this

Answer 6

u =0 becoz starting from rest

Answer 7

72 km/h = 20m/s

Answer 8

5 min = 300s

Answer 9

now find acceleration

Answer 10

use the laws of motion (physics)

Answer 11

Didn't we do this not too long ago?\[a=\frac{Delta V}{\Delta T}=\frac{20m/s}{(5*60s)}=?\]

Answer 12

20 = 0 + 300a

a = 20/300 = 0.066

Answer 13

m/s^2

Answer 14

s = ut + 1/2 a t^2

s = 0 + 1/2 * 0.06 * 300 *300 = 2700 m

Answer 15

yup