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b. Find the equation of the tangent line to the graph of f at the point (−2, 8).
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where is f?
well the question above it said Let f be the function defined as f(x) = 3x2 − 4. 3x^2 a. Use the definition of the derivative to find f′(x) b.and my anserw was 6x
f(x) = 3x2− 4. 3x^2 ?? like this?
no \[f(x)=3x^2-4\]
f'(x) =6x f'(-2)=6(-2) =-12 so line equation is: y+2=-12(x-8)
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O ok thanks I got the same thing to.
good job
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