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What is the fourth term in the expansion of (x + 2)6? 480x 168x4 160x3 120x3
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Fourth term will be: \[\huge T_4 = ^6C_3 \times (x)^3 \times (1)^3\] Can you find its value??
whats t stand for and c
T is for 4rth term and C stands for combination..
the fourth term will be \(\dbinom{6}{3}x^3\times 2^3\) \[\dbinom{6}{6}=\frac{6\times 5\times 4}{3\times 2}=5\times 4=20\] \[2^3=8\] answer is \(8\times 20x^3=160x^3\)
\[\huge ^nC_r = \frac{n!}{(n-r)! \times r!}\]
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