Question

\[x-2^{y}=0\]
\[2^{x}+2^{y}=6\]
please help me !

Answer 1

You'll need to make use of log\(_2\) , use that on both sides of the second equation for instance and what do you get? ;-)

Answer 2

\[\huge \log_b b^{\text{x}} = \text{x}\]

Answer 3

@Muskan do you follow?

Answer 4

yes...
how to solve this equation?
with log

Answer 5

i would have just done guess n check
x = 2, y = 1

but using log is the correct way of solving. but here the solution may become complex...