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Solve 2^(x + 3) = 7
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hello.... do you know how to write exponential equations into logarithmic equations?
like make it (x+3)log2=7?
ie... \[\large b^x=M \rightarrow log_bM=x\]
what does ie mean
ie means "in other words.."
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ok
which number would be b
b would be the base of your log (and the base in your exponential equation)
that's the 2.
so log 2 =.3010299957
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brb...
can you help me set up the problem
....
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