Solve for x: (3/x)-(2/3)=5/6
yes
multiply every term by 6x to eliminate the denominators \[\frac{3\times6x}{x} - \frac{ 2\times6x}{3} = \frac{5 \times6x}{6} \] then 18 - 4x = 5x
3 - 2x/3 = 5x/6 18/6 - 4x/6 = 5x/6 18/6 = (4x + 5x)/6 18/6 = 9x/6 3 = 3/2x 2 = x
You don't really have to multiply every term by x to solve this
another question i am having difficulty with is solve for x: 5/x^2 - 2/x = 2/x+1
the options are x= 1/4 and x = 2 x= -1/4 and x = -2 x= 1/4 and x=-2 x=-1/4 and x=2
You should have recognized the mistake I made when I used x - 1 instead of x + 1
\(\frac{5}{x^2} - \frac{2}{x} = \frac{2}{x+1}\) \(\frac{5}{x^2} - \frac{2x}{x^2} = \frac{2}{x+1}\) \(\frac{5 - 2x}{x^2} = \frac{2}{x+1}\) \(2x^2 = (x+1)(5-2x)\) \(2x^2 = -2x^2 + 3x + 5\) \(4x^2 - 3x - 5=0\) Okay, I'm pretty sure that is correct, so now you have to double check to make sure you put the right problem and the right answer choices.
You must be talking about the first problem
\(\frac{3}{x} - \frac{2}{3} = \frac{5}{6}\) \(\frac{3}{x} - \frac{4}{6} = \frac{5}{6}\) \(\frac{3}{x} = \frac{5}{6} + \frac{4}{6}\) \(\frac{3}{x} = \frac{9}{6}\) \(18 = 9x\) \(\frac{18}{9} = x\) 2 = x
You're not communicating with me so I have no idea which set of answer choices the problem you're working on refers to
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