Question

2401^(2n)=343^(n+2)

Answer 1

Get those two bases to be the same base first. 2401 and 343 are both powers of what? Then rewrite them with that base.

Answer 2

so 7^2n = 7^(n+2) now what do i do?

Answer 3

\[2401^{2n} = 343^{n+2}\]
\[7^{4(2n)} = 7^{3(n+2)}\]
\[7^{(8n)} = 7^{(3n+6)}\]
8n = 3n + 6
8n - 3n = 6
5n = 6
n = 6/5

Answer 4

@fitzmaths...PLEASE don't just give answers. There's absolutely no incentive to learn if you do this.

Answer 5

@shandelman ok, i understand your point.
@Rainbow_Dash hope it helped and that you can now do another problem by yourself