Question

f(x)=(x+5)^2(x-3)^2
for intercepts I got:
x (-5,0),(3,0)
y (0,225)

Answer 1

Hmm... May I know what your question is?

Answer 2

did i do this correct

Answer 3

Yes.
For x-int, put f(x) = 0
0 = (x+5)^2(x-3)^2
(x+5)^2=0 or (x-3)^2=0
x = -5 or x = 3
So, x-int are at ( -5, 0) and (3, 0)

For y-int,
y-int = f(0) = (0+5)^2(0-3)^2 = 5^2 ( -3)^2 = 25 (9) = 225
So, y-int is at (0, 225)

Answer 4

thank you

Answer 5

Welcome :)