Question

9^(10n-12)=1/6561

Answer 1

Seems you like these!!!
\[9^{10n-12}= 1/6561\]
\[\log_{10}9^{10n-12} = log_{10}1/6561\]
\[(10n-12)\log_{10}9^{} = log_{10}1/6561\]
(10n-12) x 0.95424 = -3.81697
9.5424n - 11.4509 = -3.81697
9.5424n = -3.81697 + 11.4509
9.5424n = 7.63394
n = 7.63394/9.5424
n = 0.8

Answer 2

\[9^{(10n-12)}=\frac{1}{6561}\]\[9^{(10n-12)}=\frac{1}{9^4}\]\[9^{(10n-12)}=9^{-4}\]10n-12 = -4
Now, can you solve it?