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What is needed to prove ΔBCA ≅ ΔEFD by AAS?
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here's the picture i hope it helps, really confused not sure if i did it right
do you know what AAS stands for?
AAS = angle angle side your problem already gives FD=CA (side) and <EFD = <ACB (angle) so it would need another angle
no i dont know what it stands for lol
please explain :(
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nothing is needed. if the a leg and an angle of 2 right triangles are congruent, the triangle by sa or hl
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