Question

Can anyone answer...

Find the equation of the tangent line to the graph of f at the point (-2,8)

Answer 1

What is the graph f?

Answer 2

y-8=f'(-2)*(x+2)

Answer 3

What is the equation which describes f(x) ?

Answer 4

the equation of the tangent of the graph of the function f(x) at (-2,8) [it must be 8=f(-2) ]is : \[y-8=f'(x)(x+2)\] such that \[f'(0)=[f(0)-8]/2\]

Answer 5

To do this question, you'll need to take the derivative of the function f(x), which is the tangent line.

Answer 6

Although you'd have to give us the equation that describes \(f(x)\)