Question

construct a truth table for ~p-->~q

Answer 1

this is pretty straight forward. do you know how to start it?

Answer 2

no I don't

Answer 3

\[
\begin{array}{|c|c|c|c}
p
& q
& \lnot{}p
& \lnot{}q \\
\hline
t & t & f & f \\
t & f & f & t\\
f & t & t & f \\
f & f & t & t \\
\hline
\end{array}
\]

Answer 4

the first two columns give the four possible combinations of \(p\) and \(q\) being true or false

Answer 5

the second two columns are the negation of each one
that is, where \(p\) had a \(t\), we put \(\lnot p\) as \(f\) and vice versa

Answer 6

is that clear so far?

Answer 7

yes

Answer 8

for the last column we need to put \(\lnot p\implies \lnot q\) we look only at the second two columns, and ignore the first two

Answer 9

a statement of that form is only false is the first one is true and the second one is false.
otherwise it is true
you get
\[\begin{array}{|c|c|c|c|c}
p
& q
& \lnot{}p
& \lnot{}q
& \lnot{}p\Rightarrow{}\lnot{}q \\
\hline
t & t & f & f & t \\
t & f &f & t & t \\
f & t & t & f & f \\
f & f & t & t & t \\
\hline
\end{array}\]

Answer 10

takes a while to wrote these here

Answer 11

if you would like to generate your own truth table, which use 0 and 1 for F and T
i can send you a link

Answer 12

ok I would like that

Answer 13

obviously you will have to do a little work to get the syntax correct, but they tell you what to write
http://www.kwi.dk/projects/php/truthtable/?

Answer 14

make up your own and hit "display truth table" to get your answer

Answer 15

ok and thanks