Question

puzzle question :

1_2_3_4_5_6_7_8_9 = 100
fill " _ " with +, -, or * so that LHS=RHS
note that bodmas rule doesn't apply here.

Answer 1

\[(-1+(2\times3)) \times (4\times5)-6+7+8-9 = 100\]

Answer 2

you used brackets, also theres no _ before 1 ..
so i wont take that as the ans @UnkleRhaukus

Answer 3

bother

Answer 4

??

Answer 5

so what are the rules on the order of operations?
do you have to do them from left to right, or...?

Answer 6

i'll show an example
1+2*3*4-5+6+7-8*9=324
you see now??

Answer 7

so that would be a "yes"
you did not do the multiplication first

Answer 8

and you cannot chose how to arrange the order, you do it from left to right

Answer 9

i dont get it
1+2*3*4-5+6+7-8*9=39

Answer 10

he did it like
[(1+2)*3*4-5+6+7-8]*9

Answer 11

*=-39

Answer 12

left to right...

Answer 13

[(1+2)*3*4-5+6+7-8]*9
[3*3*4-5+6+7-8]*9
(36)*9=324

Answer 14

oh

Answer 15

36*9 = 324

whats the problem? its left to right, where all +,- and * have same priority..

Answer 16

well not same priority,,but you have to go left to right..

Answer 17

ah like this?
\[((((((((1\star2)\star3)\star4)\star5)\star6)\star7)\star8)\star9) = 100\]

Answer 18

yep//take it like that..

Answer 19

division not allowed, right?

Answer 20

i had my ans without division, i'd like to know a soln without division if you can tell..

Answer 21

1*2+3*4*5*+6-7-8+9
pretty sure that does the job...

Answer 22

yep..matches with my soln ! :)

Answer 23

very cool Q!
I've had it for a few minutes, but my browser crashed :(